The supermarket has a few checkouts, and the list says how many people wait at each one, numbered from 1. Write best_counter(queues) to return the number of the shortest queue. On a tie, pick the lower number.
best_counter([5, 2, 7])→2best_counter([0, 3])→1best_counter([4, 1, 6, 1])→2def best_counter(queues):
fewest = min(queues)
# your code here: where fewest sits, plus 1 for the checkout number
return 0
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